(2,3)R; (1,2)R; (1,2)R; (1,2)R; (1,2)R; (1,2)R; (1,2)
If (2,1),(3,2)R, R is symmetric.
R=(1,1),(2,2),(3,3),(2,1),(3,2),(2,3),(1,2) is now equal to R=(1,1),(2,2),(3,3),(2,1),(3,2),(2,3),(1,2)
If (3,1);(1,3)R, R is transitive. As a result, R becomes and
(1,1)(2,2)(3,3)(2,1)(3,2)(1,3) equivalence relation by adding (1,1)(2,2)(3,3)(2,1)(3,2)(1,3) (1,2). Hence,
There are a total of seven ordered pairs.